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1. And then A transpose would be n by
m
2. when we got a Fibonacci number that's bigger than
M
.
3. we get
m
1 plus p over p squared.
4. All's we've got to plug in is
m
, the payment every year,
5. [/i] and the slash
m
[/
m
] as in Mike switch.
6. So
m
equals 0 implies that S is equal to the empty set.
7. So the base case is
m
equals 0.
8. [
M
] Oooh- Something is loose in my pizzeria!?
9. an n-year $
m
-dollar payment annuity,
10. [ominous ambience] [
M
] Uh-oh, why?
11. i"
m
going to start the game guys
12. there's
M
faculty lines.
13. for the n when f of n is bigger and equal to
M
,
14. PROFESSOR: Log of
M
. So the jobs get filled in log of
M
years.
15. So the value for
m
is $50,000, and at 6% V is only $883,000.
16. punch out here and gone a gun=
m
with a
17. And I"
m
going to start with my New England Patriots example.
18. So the total number of jobs is
M
, and that's a fixed value.
19. of n plus 1 times
m
.
20. [
M
]Ohh, wait, he moved......Wait.....He moved! [T] Begin audio prompt in three.. two... one...
21. So the first year, the company generates
m
dollars,
22. do the line integral it becomes
M
dx N dy.
23. dollars is 450
m
and
M
thank you a
24. [
M
] What!? [Soft, peppy music and sound effects]
25. So let's reread this statement where
m
is equal to 0.
26. To see when all the jobs are filled, all
M
jobs,
27. Let's see. What if I take
M
sub y?
28. red, blue, brown, whatever.. green. They supposedly create those
M
&M's in a particular distribution.
29. And so that's going to be worth
m
over 1 plus p
30. That's worth
m
over 1 plus p squared,
31. So the value of the annuity is
m
times 1 minus x to the n
32. We assume that P of
m
holds.
33.
m
dollars at the beginning of each year for n years, what
34. Every year the company grows its bottom line by
m
dollars.
35. The next payment is
m
dollars in one year,
36. AUDIENCE: --where S right now is
m
over 1 plus p--
37. And peanut
M
&Ms.
38. This equals-- we'll pull the
m
out in front--
39. AUDIENCE: Log of
M
?
40. sub x -
M
sub y. It is just replicating the
41. and so that's going to be worth
m
over 1 plus p today.
42. in terms of theta of something to do with some function of
M
?
43. Let's try to think about it. We want to call this guy
M
.
44. equals 1 to
m
of the log of the individual ratio.
45. over
m
, which is the mass.
46. Real popular example is about if the percent... like for
M
&M's come in different colors of
47. particles, and
m
, of course, is equal to the
48. e-s-c-r-i-
m
-a
49. Now we have a third thing which is N sub x equals
M
sub y at
50. the next year 3
m
, the next year 4
m
,
51. and it works by paying
m
dollars at the start of each year,
52. I'm taking
m
observations.
53. let's call this guy N. If you look at partial
M
,
54. And let S be the first
m
selected edges.
55. If we look at this for each
m
greater than or equal to 1,
56. and we have this particular variable
m
.
57. the next year is three
m
dollars.
58.
M
- Ya so the ambient recording is kind of the invisible
59. [
M
] Something's loose in my pizzeria??
60. C; 2 0 - 1; 1 1 0|. And let's call that
M
.
61. Dewey
M
Johnson Bridge Doctor Chattahoochee, FL 32324
62. negative y and x then this curl is going to be N sub x minus
M
63. Here's our base case again. n is equal to 0 or
m
is equal to
64. I'm going to take negative
m
and add the recursive result
65. Here's our base case again. n is equal to 0 or
m
is equal to
66. [
M
] Okay... [Narr.] There's a big party here Saturday.
67. But what he doesn't say is that the release date is totally unthinkable and the super suit is
m
68. when the determinant of
M
is zero.
69. S that consists of the first
m
selected edges,
70. The stronger I got, the lesser my hair were, And now I,
m
a baldy, and stronger as well.
71. of
m
over 1 plus p to the i.
72.
M
minus the tiny thing.
73. Dewey
M
Johnson Bridge, Chattahoochee, Florida
74. Now, what we really care about is what's $1, or
m
dollars,
75. So the first year it pays n dollars, the next year 2
m
,
76. word with stress on the first syllable. DA-da, monkey. It begins with the
M
consonant sound,
77.
m
to result n times.
78.
M
- This will also keep a list of Bens web browsing history.
79. So let S consist, for example, of the first
m
edges.
80. [
M
] Wha...
81. -
M
-hmm. - and transistor and resisters.
82. Well, then all I'm going to do is take
m
and just add it to
83. And we know that we can apply p of
m
for S, right?
84. Let S denote the first
m
selected edges.
85. then the transformation
M
, actually I undo the
86. We want to call that guy N. And we want to test
M
sub y
87. and we get
m
1 minus 1 over 1 plus p
88. So when are all
M
jobs filled by this process?
89. fails our test. Well, let's call this
M
and
90.
M
- We live in a golden age of convenience enabled by technology.
91. is a matrix
M
, with the property that if I
92. the next year it generates two
m
dollars in profit,
93. skyrim weapon it is the blade of sacrifice it is a unique
M
&E dagger that
94. The
M
in MIT would stand for Maui, instead of
95. Your question is if I have the property
M
sub y equals N sub x
96. So when are all
M
jobs filled by this process?
97.
M
- Can you be said to be practicing journalism in a
98. then the value of this annuity is just
m
times 1
99. Instead of $1 each year, it's
m
so there's an
m
out front.
100. And so that's going to be worth
m
over 1 plus p
101. let's say
M
and N compliments, is a gradient field.
102. So let E denote the edge that I added in the
m
plus 1 step.
103. But you can solve it exactly now by just plugging in whatever
M
104. We know f sub xy equals f sub yx, and that means
M
sub y
105. [Ominous background ambience begins] [
M
] Ooh.
106. multiply A by
M
, then I get identity.
107. And so, for example, if we made
m
be $50,000,
108. So we'll use induction on
m
.
109. It's the n-th payment, so it's
m
dollars in n minus 1 years.
110. that,
m
times 1 plus p over p, because the limit as n
111. We assume that P of
m
holds.
112. or n by n or
m
by n array of special numbers.
113. are essentially
m
and may, as a rule,
114. and since it's being paid now, that's worth
m
dollars.
115. [
M
] Ooookay alriiiight alright alri- [Mechanical laugh]
116. is bigger than or equal to
M
?
117. because A could be
m
by n.
118. Let's just admit it. The matrix
M
will be denoted by
119. matrix is not invertible.
M
is not invertible exactly
120. Yeah, I know I"
m
still in my Scorpion outfit but you'll just have to pretend that I'm Kano
121. And the next payment is
m
dollars in two years.
122. [
M
] 'Kay.
123. And, if I multiply
M
by A, I also get identity.
124. and they "wa", go like a "w". So... And the "mail",
m
-a-i-l,
125.
M
equals 10,000 into this expression,
126. And let S be the first
m
selected edges.
127. For what value of n is f of n bigger than
M
?
128. adds in
m
dollars more of profit.
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