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g acceleration of gravity


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    1. connected, and with the same vertices as G.
    2. So I have to prove that for all G,
    3. because we showed that for all graphs G,
    4. there exists a minimum spanning tree of G.
    5. So what I need to proof is that for all G,
    6. with the same vertices of G. So the only difference
    7. And we assume that it has the same vertices of G of course.
    8. We said that a connected graph, G-- that's
    9. Do we still have a connected subgraph of G
    10. So what I need to proof is that for all G,
    11. So we know a subgraph of G that touches all the different edges
    12. So we say for all G and for all sets
    13. So this is the minimum spanning tree for the graph G
    14. a connected graph G.
    15. So let this be a connected subgraph of G.
    16. It's defined as the spanning tree of G such
    17. that covers all the vertices of G?
    18. Well, of course it cover all the vertices of G
    19. There does not exist a connected graph G that has no ST.
    20. So this is the minimum spanning tree for the graph G
    21. let T be a connected subgraph of G, but with a property
    22. there exists a minimum spanning tree of G such
    23. So all vertices in G are still connected
    24. What is G?
    25. is that for any connected weighted graph G,
    26. What is G?
    27. For all G, I still need to prove there
    28. So we already know that T is a connected subgraph of G
    29. It's defined as the spanning tree of G such
    30. Do we still have a connected subgraph of G

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